Defect in XSH modf()

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        Defect report from : Ulrich Drepper , Red Hat

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@ page 778 line 25505 section modf() editorial {ud-7}

Problem:

Defect code :  1. Error

The example in the app usage for modf is:

  a = modf(x, &iptr) ;
  x == a+*iptr ;

The first line suggests that iptr is of type double, the second line that it is 
of type double*.

Action:

The prototypes and the discussion in the RETURN VALUE section introduce iptr as 
of type double*.  Be consistent, change the example to

  a = modf(x, iptr) ;
  x == a+*iptr ;

(note the missing & in the first line).