Re: Re: Re: Re: value of $? in trap handler after exit n

[Geoff Clare <yyy@xxxxxxxxxxxxx>]

Joerg Schilling <yyyyyyyyyyyyyyy@xxxxxxxxxxxxxxxxxxx> wrote, on 11 Nov 2006:
>
> > Interestingly, the POSIX shells on Solaris 10 and HP-UX 11 are both
> > inconsistent here.  They treat $? one way, but a plain "exit" the
> > other way:
> >
> > $ sh -c "trap 'echo \$?' EXIT && exit 1"     
> > 0
> > $ sh -c 'trap "exit" EXIT; exit 3' ; echo $?
> > 3
> 
> On Solaris 9 .. 11, this prints 0 in both cases

Sounds like you used /bin/sh.  On Solaris 8 and 10 with the POSIX
shell (/usr/xpg4/bin/sh) I get the results shown above.

-- 
Geoff Clare <yyyyyyy@xxxxxxxxxxxxx>
The Open Group, Thames Tower, Station Road, Reading, RG1 1LX, England